Optimal. Leaf size=632 \[ \frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{-\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{-\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}-\frac {2 e \log \left (1-e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{d^3}-\frac {e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}-\frac {a+b \sin ^{-1}(c x)}{2 d^2 x^2}+\frac {b c e \tan ^{-1}\left (\frac {x \sqrt {c^2 d+e}}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt {c^2 d+e}}-\frac {i b e \text {Li}_2\left (-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {d c^2+e}}\right )}{d^3}-\frac {i b e \text {Li}_2\left (\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {d c^2+e}}\right )}{d^3}-\frac {i b e \text {Li}_2\left (-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i \sqrt {-d} c+\sqrt {d c^2+e}}\right )}{d^3}-\frac {i b e \text {Li}_2\left (\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i \sqrt {-d} c+\sqrt {d c^2+e}}\right )}{d^3}-\frac {b c \sqrt {1-c^2 x^2}}{2 d^2 x}+\frac {i b e \text {Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )}{d^3} \]
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Rubi [A] time = 1.04, antiderivative size = 632, normalized size of antiderivative = 1.00, number of steps used = 30, number of rules used = 13, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.619, Rules used = {4733, 4627, 264, 4625, 3717, 2190, 2279, 2391, 4729, 377, 205, 4741, 4521} \[ -\frac {i b e \text {PolyLog}\left (2,-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{-\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}-\frac {i b e \text {PolyLog}\left (2,\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{-\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}-\frac {i b e \text {PolyLog}\left (2,-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}-\frac {i b e \text {PolyLog}\left (2,\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}+\frac {i b e \text {PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{-\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{-\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{\sqrt {c^2 d+e}+i c \sqrt {-d}}\right )}{d^3}-\frac {e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}-\frac {2 e \log \left (1-e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{d^3}-\frac {a+b \sin ^{-1}(c x)}{2 d^2 x^2}+\frac {b c e \tan ^{-1}\left (\frac {x \sqrt {c^2 d+e}}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt {c^2 d+e}}-\frac {b c \sqrt {1-c^2 x^2}}{2 d^2 x} \]
Antiderivative was successfully verified.
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Rule 205
Rule 264
Rule 377
Rule 2190
Rule 2279
Rule 2391
Rule 3717
Rule 4521
Rule 4625
Rule 4627
Rule 4729
Rule 4733
Rule 4741
Rubi steps
\begin {align*} \int \frac {a+b \sin ^{-1}(c x)}{x^3 \left (d+e x^2\right )^2} \, dx &=\int \left (\frac {a+b \sin ^{-1}(c x)}{d^2 x^3}-\frac {2 e \left (a+b \sin ^{-1}(c x)\right )}{d^3 x}+\frac {e^2 x \left (a+b \sin ^{-1}(c x)\right )}{d^2 \left (d+e x^2\right )^2}+\frac {2 e^2 x \left (a+b \sin ^{-1}(c x)\right )}{d^3 \left (d+e x^2\right )}\right ) \, dx\\ &=\frac {\int \frac {a+b \sin ^{-1}(c x)}{x^3} \, dx}{d^2}-\frac {(2 e) \int \frac {a+b \sin ^{-1}(c x)}{x} \, dx}{d^3}+\frac {\left (2 e^2\right ) \int \frac {x \left (a+b \sin ^{-1}(c x)\right )}{d+e x^2} \, dx}{d^3}+\frac {e^2 \int \frac {x \left (a+b \sin ^{-1}(c x)\right )}{\left (d+e x^2\right )^2} \, dx}{d^2}\\ &=-\frac {a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac {e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac {(b c) \int \frac {1}{x^2 \sqrt {1-c^2 x^2}} \, dx}{2 d^2}-\frac {(2 e) \operatorname {Subst}\left (\int (a+b x) \cot (x) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac {(b c e) \int \frac {1}{\sqrt {1-c^2 x^2} \left (d+e x^2\right )} \, dx}{2 d^2}+\frac {\left (2 e^2\right ) \int \left (-\frac {a+b \sin ^{-1}(c x)}{2 \sqrt {e} \left (\sqrt {-d}-\sqrt {e} x\right )}+\frac {a+b \sin ^{-1}(c x)}{2 \sqrt {e} \left (\sqrt {-d}+\sqrt {e} x\right )}\right ) \, dx}{d^3}\\ &=-\frac {b c \sqrt {1-c^2 x^2}}{2 d^2 x}-\frac {a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac {e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac {i e \left (a+b \sin ^{-1}(c x)\right )^2}{b d^3}+\frac {(4 i e) \operatorname {Subst}\left (\int \frac {e^{2 i x} (a+b x)}{1-e^{2 i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac {(b c e) \operatorname {Subst}\left (\int \frac {1}{d-\left (-c^2 d-e\right ) x^2} \, dx,x,\frac {x}{\sqrt {1-c^2 x^2}}\right )}{2 d^2}-\frac {e^{3/2} \int \frac {a+b \sin ^{-1}(c x)}{\sqrt {-d}-\sqrt {e} x} \, dx}{d^3}+\frac {e^{3/2} \int \frac {a+b \sin ^{-1}(c x)}{\sqrt {-d}+\sqrt {e} x} \, dx}{d^3}\\ &=-\frac {b c \sqrt {1-c^2 x^2}}{2 d^2 x}-\frac {a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac {e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac {i e \left (a+b \sin ^{-1}(c x)\right )^2}{b d^3}+\frac {b c e \tan ^{-1}\left (\frac {\sqrt {c^2 d+e} x}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt {c^2 d+e}}-\frac {2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac {(2 b e) \operatorname {Subst}\left (\int \log \left (1-e^{2 i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac {e^{3/2} \operatorname {Subst}\left (\int \frac {(a+b x) \cos (x)}{c \sqrt {-d}-\sqrt {e} \sin (x)} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac {e^{3/2} \operatorname {Subst}\left (\int \frac {(a+b x) \cos (x)}{c \sqrt {-d}+\sqrt {e} \sin (x)} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}\\ &=-\frac {b c \sqrt {1-c^2 x^2}}{2 d^2 x}-\frac {a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac {e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac {b c e \tan ^{-1}\left (\frac {\sqrt {c^2 d+e} x}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt {c^2 d+e}}-\frac {2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}-\frac {(i b e) \operatorname {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{2 i \sin ^{-1}(c x)}\right )}{d^3}-\frac {\left (i e^{3/2}\right ) \operatorname {Subst}\left (\int \frac {e^{i x} (a+b x)}{i c \sqrt {-d}-\sqrt {c^2 d+e}-\sqrt {e} e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac {\left (i e^{3/2}\right ) \operatorname {Subst}\left (\int \frac {e^{i x} (a+b x)}{i c \sqrt {-d}+\sqrt {c^2 d+e}-\sqrt {e} e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac {\left (i e^{3/2}\right ) \operatorname {Subst}\left (\int \frac {e^{i x} (a+b x)}{i c \sqrt {-d}-\sqrt {c^2 d+e}+\sqrt {e} e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac {\left (i e^{3/2}\right ) \operatorname {Subst}\left (\int \frac {e^{i x} (a+b x)}{i c \sqrt {-d}+\sqrt {c^2 d+e}+\sqrt {e} e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}\\ &=-\frac {b c \sqrt {1-c^2 x^2}}{2 d^2 x}-\frac {a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac {e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac {b c e \tan ^{-1}\left (\frac {\sqrt {c^2 d+e} x}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt {c^2 d+e}}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{d^3}-\frac {2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac {i b e \text {Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )}{d^3}-\frac {(b e) \operatorname {Subst}\left (\int \log \left (1-\frac {\sqrt {e} e^{i x}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac {(b e) \operatorname {Subst}\left (\int \log \left (1+\frac {\sqrt {e} e^{i x}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac {(b e) \operatorname {Subst}\left (\int \log \left (1-\frac {\sqrt {e} e^{i x}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac {(b e) \operatorname {Subst}\left (\int \log \left (1+\frac {\sqrt {e} e^{i x}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}\\ &=-\frac {b c \sqrt {1-c^2 x^2}}{2 d^2 x}-\frac {a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac {e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac {b c e \tan ^{-1}\left (\frac {\sqrt {c^2 d+e} x}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt {c^2 d+e}}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{d^3}-\frac {2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac {i b e \text {Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac {(i b e) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {\sqrt {e} x}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{d^3}+\frac {(i b e) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {\sqrt {e} x}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{d^3}+\frac {(i b e) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {\sqrt {e} x}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{d^3}+\frac {(i b e) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {\sqrt {e} x}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{d^3}\\ &=-\frac {b c \sqrt {1-c^2 x^2}}{2 d^2 x}-\frac {a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac {e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac {b c e \tan ^{-1}\left (\frac {\sqrt {c^2 d+e} x}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt {c^2 d+e}}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{d^3}+\frac {e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{d^3}-\frac {2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}-\frac {i b e \text {Li}_2\left (-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{d^3}-\frac {i b e \text {Li}_2\left (\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}-\sqrt {c^2 d+e}}\right )}{d^3}-\frac {i b e \text {Li}_2\left (-\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{d^3}-\frac {i b e \text {Li}_2\left (\frac {\sqrt {e} e^{i \sin ^{-1}(c x)}}{i c \sqrt {-d}+\sqrt {c^2 d+e}}\right )}{d^3}+\frac {i b e \text {Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )}{d^3}\\ \end {align*}
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Mathematica [F] time = 6.44, size = 0, normalized size = 0.00 \[ \int \frac {a+b \sin ^{-1}(c x)}{x^3 \left (d+e x^2\right )^2} \, dx \]
Verification is Not applicable to the result.
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fricas [F] time = 0.67, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b \arcsin \left (c x\right ) + a}{e^{2} x^{7} + 2 \, d e x^{5} + d^{2} x^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.59, size = 679, normalized size = 1.07 \[ -\frac {c^{2} a e}{2 d^{2} \left (c^{2} e \,x^{2}+c^{2} d \right )}+\frac {a e \ln \left (c^{2} e \,x^{2}+c^{2} d \right )}{d^{3}}-\frac {a}{2 d^{2} x^{2}}-\frac {2 a e \ln \left (c x \right )}{d^{3}}-\frac {i b \sqrt {c^{2} d \left (c^{2} d +e \right )}\, \arctanh \left (\frac {2 \left (i c x +\sqrt {-c^{2} x^{2}+1}\right )^{2} e -4 c^{2} d -2 e}{4 \sqrt {d^{2} c^{4}+c^{2} e d}}\right ) e}{2 \left (c^{2} d +e \right ) d^{3}}+\frac {i c^{4} b}{2 \left (c^{2} e \,x^{2}+c^{2} d \right ) d}-\frac {c^{3} b x \sqrt {-c^{2} x^{2}+1}\, e}{2 \left (c^{2} e \,x^{2}+c^{2} d \right ) d^{2}}-\frac {c^{3} b \sqrt {-c^{2} x^{2}+1}}{2 x \left (c^{2} e \,x^{2}+c^{2} d \right ) d}-\frac {c^{2} b \arcsin \left (c x \right ) e}{d^{2} \left (c^{2} e \,x^{2}+c^{2} d \right )}-\frac {c^{2} b \arcsin \left (c x \right )}{2 x^{2} \left (c^{2} e \,x^{2}+c^{2} d \right ) d}-\frac {i b \,e^{2} \left (\munderset {\textit {\_R1} =\RootOf \left (e \,\textit {\_Z}^{4}+\left (-4 c^{2} d -2 e \right ) \textit {\_Z}^{2}+e \right )}{\sum }\frac {\left (\textit {\_R1}^{2}-1\right ) \left (i \arcsin \left (c x \right ) \ln \left (\frac {\textit {\_R1} -i c x -\sqrt {-c^{2} x^{2}+1}}{\textit {\_R1}}\right )+\dilog \left (\frac {\textit {\_R1} -i c x -\sqrt {-c^{2} x^{2}+1}}{\textit {\_R1}}\right )\right )}{\textit {\_R1}^{2} e -2 c^{2} d -e}\right )}{2 d^{3}}-\frac {i b e \left (\munderset {\textit {\_R1} =\RootOf \left (e \,\textit {\_Z}^{4}+\left (-4 c^{2} d -2 e \right ) \textit {\_Z}^{2}+e \right )}{\sum }\frac {\left (\textit {\_R1}^{2} e -4 c^{2} d -e \right ) \left (i \arcsin \left (c x \right ) \ln \left (\frac {\textit {\_R1} -i c x -\sqrt {-c^{2} x^{2}+1}}{\textit {\_R1}}\right )+\dilog \left (\frac {\textit {\_R1} -i c x -\sqrt {-c^{2} x^{2}+1}}{\textit {\_R1}}\right )\right )}{\textit {\_R1}^{2} e -2 c^{2} d -e}\right )}{2 d^{3}}-\frac {2 b e \arcsin \left (c x \right ) \ln \left (1+i c x +\sqrt {-c^{2} x^{2}+1}\right )}{d^{3}}+\frac {2 i b e \dilog \left (1+i c x +\sqrt {-c^{2} x^{2}+1}\right )}{d^{3}}+\frac {i c^{4} b \,x^{2} e}{2 \left (c^{2} e \,x^{2}+c^{2} d \right ) d^{2}}-\frac {2 i b e \dilog \left (i c x +\sqrt {-c^{2} x^{2}+1}\right )}{d^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {1}{2} \, a {\left (\frac {2 \, e x^{2} + d}{d^{2} e x^{4} + d^{3} x^{2}} - \frac {2 \, e \log \left (e x^{2} + d\right )}{d^{3}} + \frac {4 \, e \log \relax (x)}{d^{3}}\right )} + b \int \frac {\arctan \left (c x, \sqrt {c x + 1} \sqrt {-c x + 1}\right )}{e^{2} x^{7} + 2 \, d e x^{5} + d^{2} x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {a+b\,\mathrm {asin}\left (c\,x\right )}{x^3\,{\left (e\,x^2+d\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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